Measuring Time Content

Suppose you are given a black box with some unknown signal $f(t)$ in it, and the only thing you can do is to provide another signal $in(t)$ as input, in which case the black box will output the scalar product between the two: $\langle f(t), in(t)\rangle$.

What kind of input signal should you use to get the value of $f(\Delta)$?

1.0
1.0 20.0
0.0
-3.0 3.0
Open for comments

The three plots on the top left show the unknown function $f(t)=\cos(3t)$. The next three plots show possible candidates for $in(t)$: rectangle, triangle and sinc functions which can be modified using sliders $a$ and $\Delta$. Notice that the integral of these three functions is always 1, whatever $a$.

In the three bottom left plots, we multiply our three functions $in(t)$ with $f(t)$. Then we compute and print the scalar product as the integral of this product, i.e. the signed area in blue.

$$ \langle f(t),in(t-\Delta)\rangle=\int_{-\infty}^{\infty} f(t)\,in(t-\Delta)\,dt $$

When $a$ grows, we see that our three functions, although not fully identical, tend to have the same effect when used in the integral: only their values very close to their maximum contribute to the result.

When $a$ tends to infinity (here, to 20), these functions can no longer be plotted. They are therefore termed as a Dirac impulse $\delta(t)$ and symbolically represented on the right plots as an arrow, the amplitude of which is set to the integral of the functions: 1 on the top plot and $f(\Delta)$ on the bottom plot.

As a matter of fact, we see that when $\Delta$ is set to 0, all integrals tend to $f(0)$:

$$ \langle f(t),\delta(t)\rangle=\int_{-\infty}^{\infty} f(t)\,\delta(t)\,dt=f(0) $$

When $\Delta$ is modified, all integrals tend to $f(\Delta)$:

$$ \langle f(t),\delta(t-\Delta)\rangle=\int_{-\infty}^{\infty} f(t)\,\delta(t-\Delta)\,dt=f(\Delta) $$

The ideal input function $in(t)$ is therefore $\delta(t-\Delta)$.